Moved from GitHub dgraph/1747 Posted by abbas-zaidi : RIDE is a node and DRIVER and RIDER are edges coming out of RIDE. Driver and RIDER are different nodes as well. I need to query the rides which has the same driver-rider pair. { q(func:eq(name,"RIDE")) @groupby(rider,driver) { count(_ui…

Group by should allow filters

diggy (Dgraph Bot) October 3, 2018, 5:28am 3

mehdiym commented :

I have the same request in order to remove duplicate nodes in my database.

Topic		Replies	Views
Groupby does not support predicate of list type Dgraph dgraph , kind:enhancement , status:needs-attenti , area:querylang:group	7	885	March 1, 2021
Filtering issue Dgraph kind:question , dgraph	1	271	November 9, 2020
Find nodes with edges to nodes filtered by type Dgraph	5	521	February 12, 2020
As a user, I would like to group by "value" instead of just edges Dgraph dgraph , kind:enhancement , status:needs-attenti , area:querylang:group	0	689	May 10, 2020
Remove Duplicates from Results GraphQL graphql , dgraph	3	2643	September 1, 2020