I am using DGraphClient in Java. I have too many concurrent mutations and queries coming in at the same time.
Do I need to a pool of DGrpahClient object or it is handled inside DGrphClient itself.
How does gRPC internally manage the concurrent Transactions? Please explain.
import io.dgraph.DgraphClient;
import io.dgraph.DgraphGrpc;
import io.dgraph.DgraphGrpc.DgraphStub;
import io.grpc.ManagedChannel;
import io.grpc.ManagedChannelBuilder;
public class DgraphExample {
public static void main(String[] args) {
// Create a gRPC channel
ManagedChannel channel = ManagedChannelBuilder.forAddress("localhost", 9080).usePlaintext().build();
DgraphStub stub = DgraphGrpc.newStub(channel);
DgraphClient dgraphClient = new DgraphClient(stub);
// Create a thread pool for concurrent operations
int threadPoolSize = 10;
ExecutorService executorService = Executors.newFixedThreadPool(threadPoolSize);
// Submit tasks to the thread pool
for (int i = 0; i < 100; i++) {
executorService.submit(() -> performOperation(dgraphClient));
}
// Shutdown the thread pool
executorService.shutdown();
}
private static void performOperation(DgraphClient dgraphClient) {
try {
// Create a new transaction
io.dgraph.Transaction txn = dgraphClient.newTransaction();
// Perform a mutation or query
String query = "{\n" +
" q(func: has(name)) {\n" +
" name\n" +
" }\n" +
"}";
io.dgraph.Response response = txn.query(query);
// Commit the transaction
txn.commit();
// Process the response
System.out.println("Response: " + response.getJson().toStringUtf8());
} catch (Exception e) {
e.printStackTrace();
}
}
}